Integrand size = 18, antiderivative size = 208 \[ \int \frac {(a+b x)^{3/2} (A+B x)}{x^7} \, dx=\frac {b (7 A b-12 a B) \sqrt {a+b x}}{160 a x^4}+\frac {b^2 (7 A b-12 a B) \sqrt {a+b x}}{960 a^2 x^3}-\frac {b^3 (7 A b-12 a B) \sqrt {a+b x}}{768 a^3 x^2}+\frac {b^4 (7 A b-12 a B) \sqrt {a+b x}}{512 a^4 x}+\frac {(7 A b-12 a B) (a+b x)^{3/2}}{60 a x^5}-\frac {A (a+b x)^{5/2}}{6 a x^6}-\frac {b^5 (7 A b-12 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{512 a^{9/2}} \]
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Time = 0.07 (sec) , antiderivative size = 208, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {79, 43, 44, 65, 214} \[ \int \frac {(a+b x)^{3/2} (A+B x)}{x^7} \, dx=-\frac {b^5 (7 A b-12 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{512 a^{9/2}}+\frac {b^4 \sqrt {a+b x} (7 A b-12 a B)}{512 a^4 x}-\frac {b^3 \sqrt {a+b x} (7 A b-12 a B)}{768 a^3 x^2}+\frac {b^2 \sqrt {a+b x} (7 A b-12 a B)}{960 a^2 x^3}+\frac {(a+b x)^{3/2} (7 A b-12 a B)}{60 a x^5}+\frac {b \sqrt {a+b x} (7 A b-12 a B)}{160 a x^4}-\frac {A (a+b x)^{5/2}}{6 a x^6} \]
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Rule 43
Rule 44
Rule 65
Rule 79
Rule 214
Rubi steps \begin{align*} \text {integral}& = -\frac {A (a+b x)^{5/2}}{6 a x^6}+\frac {\left (-\frac {7 A b}{2}+6 a B\right ) \int \frac {(a+b x)^{3/2}}{x^6} \, dx}{6 a} \\ & = \frac {(7 A b-12 a B) (a+b x)^{3/2}}{60 a x^5}-\frac {A (a+b x)^{5/2}}{6 a x^6}-\frac {(b (7 A b-12 a B)) \int \frac {\sqrt {a+b x}}{x^5} \, dx}{40 a} \\ & = \frac {b (7 A b-12 a B) \sqrt {a+b x}}{160 a x^4}+\frac {(7 A b-12 a B) (a+b x)^{3/2}}{60 a x^5}-\frac {A (a+b x)^{5/2}}{6 a x^6}-\frac {\left (b^2 (7 A b-12 a B)\right ) \int \frac {1}{x^4 \sqrt {a+b x}} \, dx}{320 a} \\ & = \frac {b (7 A b-12 a B) \sqrt {a+b x}}{160 a x^4}+\frac {b^2 (7 A b-12 a B) \sqrt {a+b x}}{960 a^2 x^3}+\frac {(7 A b-12 a B) (a+b x)^{3/2}}{60 a x^5}-\frac {A (a+b x)^{5/2}}{6 a x^6}+\frac {\left (b^3 (7 A b-12 a B)\right ) \int \frac {1}{x^3 \sqrt {a+b x}} \, dx}{384 a^2} \\ & = \frac {b (7 A b-12 a B) \sqrt {a+b x}}{160 a x^4}+\frac {b^2 (7 A b-12 a B) \sqrt {a+b x}}{960 a^2 x^3}-\frac {b^3 (7 A b-12 a B) \sqrt {a+b x}}{768 a^3 x^2}+\frac {(7 A b-12 a B) (a+b x)^{3/2}}{60 a x^5}-\frac {A (a+b x)^{5/2}}{6 a x^6}-\frac {\left (b^4 (7 A b-12 a B)\right ) \int \frac {1}{x^2 \sqrt {a+b x}} \, dx}{512 a^3} \\ & = \frac {b (7 A b-12 a B) \sqrt {a+b x}}{160 a x^4}+\frac {b^2 (7 A b-12 a B) \sqrt {a+b x}}{960 a^2 x^3}-\frac {b^3 (7 A b-12 a B) \sqrt {a+b x}}{768 a^3 x^2}+\frac {b^4 (7 A b-12 a B) \sqrt {a+b x}}{512 a^4 x}+\frac {(7 A b-12 a B) (a+b x)^{3/2}}{60 a x^5}-\frac {A (a+b x)^{5/2}}{6 a x^6}+\frac {\left (b^5 (7 A b-12 a B)\right ) \int \frac {1}{x \sqrt {a+b x}} \, dx}{1024 a^4} \\ & = \frac {b (7 A b-12 a B) \sqrt {a+b x}}{160 a x^4}+\frac {b^2 (7 A b-12 a B) \sqrt {a+b x}}{960 a^2 x^3}-\frac {b^3 (7 A b-12 a B) \sqrt {a+b x}}{768 a^3 x^2}+\frac {b^4 (7 A b-12 a B) \sqrt {a+b x}}{512 a^4 x}+\frac {(7 A b-12 a B) (a+b x)^{3/2}}{60 a x^5}-\frac {A (a+b x)^{5/2}}{6 a x^6}+\frac {\left (b^4 (7 A b-12 a B)\right ) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )}{512 a^4} \\ & = \frac {b (7 A b-12 a B) \sqrt {a+b x}}{160 a x^4}+\frac {b^2 (7 A b-12 a B) \sqrt {a+b x}}{960 a^2 x^3}-\frac {b^3 (7 A b-12 a B) \sqrt {a+b x}}{768 a^3 x^2}+\frac {b^4 (7 A b-12 a B) \sqrt {a+b x}}{512 a^4 x}+\frac {(7 A b-12 a B) (a+b x)^{3/2}}{60 a x^5}-\frac {A (a+b x)^{5/2}}{6 a x^6}-\frac {b^5 (7 A b-12 a B) \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{512 a^{9/2}} \\ \end{align*}
Time = 0.31 (sec) , antiderivative size = 148, normalized size of antiderivative = 0.71 \[ \int \frac {(a+b x)^{3/2} (A+B x)}{x^7} \, dx=-\frac {\sqrt {a+b x} \left (-105 A b^5 x^5+48 a^3 b^2 x^2 (A+2 B x)+256 a^5 (5 A+6 B x)-8 a^2 b^3 x^3 (7 A+15 B x)+10 a b^4 x^4 (7 A+18 B x)+64 a^4 b x (26 A+33 B x)\right )}{7680 a^4 x^6}+\frac {b^5 (-7 A b+12 a B) \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{512 a^{9/2}} \]
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Time = 0.55 (sec) , antiderivative size = 135, normalized size of antiderivative = 0.65
method | result | size |
pseudoelliptic | \(\frac {-\frac {7 x^{6} b^{5} \left (A b -\frac {12 B a}{7}\right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{512}+\frac {7 \left (\frac {32 \left (-6 B x -5 A \right ) a^{\frac {11}{2}}}{7}+x \left (-\frac {5 x^{3} b^{3} \left (\frac {18 B x}{7}+A \right ) a^{\frac {3}{2}}}{4}+b^{2} x^{2} \left (\frac {15 B x}{7}+A \right ) a^{\frac {5}{2}}-\frac {6 b x \left (2 B x +A \right ) a^{\frac {7}{2}}}{7}+\frac {8 \left (-33 B x -26 A \right ) a^{\frac {9}{2}}}{7}+\frac {15 A \sqrt {a}\, b^{4} x^{4}}{8}\right ) b \right ) \sqrt {b x +a}}{960}}{a^{\frac {9}{2}} x^{6}}\) | \(135\) |
risch | \(-\frac {\sqrt {b x +a}\, \left (-105 A \,b^{5} x^{5}+180 B a \,b^{4} x^{5}+70 a A \,b^{4} x^{4}-120 B \,a^{2} b^{3} x^{4}-56 a^{2} A \,b^{3} x^{3}+96 B \,a^{3} b^{2} x^{3}+48 a^{3} A \,b^{2} x^{2}+2112 B \,a^{4} b \,x^{2}+1664 a^{4} A b x +1536 a^{5} B x +1280 a^{5} A \right )}{7680 x^{6} a^{4}}-\frac {b^{5} \left (7 A b -12 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{512 a^{\frac {9}{2}}}\) | \(155\) |
derivativedivides | \(2 b^{5} \left (-\frac {-\frac {\left (7 A b -12 B a \right ) \left (b x +a \right )^{\frac {11}{2}}}{1024 a^{4}}+\frac {17 \left (7 A b -12 B a \right ) \left (b x +a \right )^{\frac {9}{2}}}{3072 a^{3}}-\frac {33 \left (7 A b -12 B a \right ) \left (b x +a \right )^{\frac {7}{2}}}{2560 a^{2}}+\frac {\left (281 A b -116 B a \right ) \left (b x +a \right )^{\frac {5}{2}}}{2560 a}+\left (\frac {119 A b}{3072}-\frac {17 B a}{256}\right ) \left (b x +a \right )^{\frac {3}{2}}-\frac {a \left (7 A b -12 B a \right ) \sqrt {b x +a}}{1024}}{b^{6} x^{6}}-\frac {\left (7 A b -12 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{1024 a^{\frac {9}{2}}}\right )\) | \(162\) |
default | \(2 b^{5} \left (-\frac {-\frac {\left (7 A b -12 B a \right ) \left (b x +a \right )^{\frac {11}{2}}}{1024 a^{4}}+\frac {17 \left (7 A b -12 B a \right ) \left (b x +a \right )^{\frac {9}{2}}}{3072 a^{3}}-\frac {33 \left (7 A b -12 B a \right ) \left (b x +a \right )^{\frac {7}{2}}}{2560 a^{2}}+\frac {\left (281 A b -116 B a \right ) \left (b x +a \right )^{\frac {5}{2}}}{2560 a}+\left (\frac {119 A b}{3072}-\frac {17 B a}{256}\right ) \left (b x +a \right )^{\frac {3}{2}}-\frac {a \left (7 A b -12 B a \right ) \sqrt {b x +a}}{1024}}{b^{6} x^{6}}-\frac {\left (7 A b -12 B a \right ) \operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{1024 a^{\frac {9}{2}}}\right )\) | \(162\) |
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Time = 0.23 (sec) , antiderivative size = 353, normalized size of antiderivative = 1.70 \[ \int \frac {(a+b x)^{3/2} (A+B x)}{x^7} \, dx=\left [-\frac {15 \, {\left (12 \, B a b^{5} - 7 \, A b^{6}\right )} \sqrt {a} x^{6} \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + 2 \, {\left (1280 \, A a^{6} + 15 \, {\left (12 \, B a^{2} b^{4} - 7 \, A a b^{5}\right )} x^{5} - 10 \, {\left (12 \, B a^{3} b^{3} - 7 \, A a^{2} b^{4}\right )} x^{4} + 8 \, {\left (12 \, B a^{4} b^{2} - 7 \, A a^{3} b^{3}\right )} x^{3} + 48 \, {\left (44 \, B a^{5} b + A a^{4} b^{2}\right )} x^{2} + 128 \, {\left (12 \, B a^{6} + 13 \, A a^{5} b\right )} x\right )} \sqrt {b x + a}}{15360 \, a^{5} x^{6}}, -\frac {15 \, {\left (12 \, B a b^{5} - 7 \, A b^{6}\right )} \sqrt {-a} x^{6} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + {\left (1280 \, A a^{6} + 15 \, {\left (12 \, B a^{2} b^{4} - 7 \, A a b^{5}\right )} x^{5} - 10 \, {\left (12 \, B a^{3} b^{3} - 7 \, A a^{2} b^{4}\right )} x^{4} + 8 \, {\left (12 \, B a^{4} b^{2} - 7 \, A a^{3} b^{3}\right )} x^{3} + 48 \, {\left (44 \, B a^{5} b + A a^{4} b^{2}\right )} x^{2} + 128 \, {\left (12 \, B a^{6} + 13 \, A a^{5} b\right )} x\right )} \sqrt {b x + a}}{7680 \, a^{5} x^{6}}\right ] \]
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Timed out. \[ \int \frac {(a+b x)^{3/2} (A+B x)}{x^7} \, dx=\text {Timed out} \]
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Time = 0.29 (sec) , antiderivative size = 268, normalized size of antiderivative = 1.29 \[ \int \frac {(a+b x)^{3/2} (A+B x)}{x^7} \, dx=-\frac {1}{15360} \, b^{6} {\left (\frac {2 \, {\left (15 \, {\left (12 \, B a - 7 \, A b\right )} {\left (b x + a\right )}^{\frac {11}{2}} - 85 \, {\left (12 \, B a^{2} - 7 \, A a b\right )} {\left (b x + a\right )}^{\frac {9}{2}} + 198 \, {\left (12 \, B a^{3} - 7 \, A a^{2} b\right )} {\left (b x + a\right )}^{\frac {7}{2}} - 6 \, {\left (116 \, B a^{4} - 281 \, A a^{3} b\right )} {\left (b x + a\right )}^{\frac {5}{2}} - 85 \, {\left (12 \, B a^{5} - 7 \, A a^{4} b\right )} {\left (b x + a\right )}^{\frac {3}{2}} + 15 \, {\left (12 \, B a^{6} - 7 \, A a^{5} b\right )} \sqrt {b x + a}\right )}}{{\left (b x + a\right )}^{6} a^{4} b - 6 \, {\left (b x + a\right )}^{5} a^{5} b + 15 \, {\left (b x + a\right )}^{4} a^{6} b - 20 \, {\left (b x + a\right )}^{3} a^{7} b + 15 \, {\left (b x + a\right )}^{2} a^{8} b - 6 \, {\left (b x + a\right )} a^{9} b + a^{10} b} + \frac {15 \, {\left (12 \, B a - 7 \, A b\right )} \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{a^{\frac {9}{2}} b}\right )} \]
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Time = 0.28 (sec) , antiderivative size = 240, normalized size of antiderivative = 1.15 \[ \int \frac {(a+b x)^{3/2} (A+B x)}{x^7} \, dx=-\frac {\frac {15 \, {\left (12 \, B a b^{6} - 7 \, A b^{7}\right )} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a} a^{4}} + \frac {180 \, {\left (b x + a\right )}^{\frac {11}{2}} B a b^{6} - 1020 \, {\left (b x + a\right )}^{\frac {9}{2}} B a^{2} b^{6} + 2376 \, {\left (b x + a\right )}^{\frac {7}{2}} B a^{3} b^{6} - 696 \, {\left (b x + a\right )}^{\frac {5}{2}} B a^{4} b^{6} - 1020 \, {\left (b x + a\right )}^{\frac {3}{2}} B a^{5} b^{6} + 180 \, \sqrt {b x + a} B a^{6} b^{6} - 105 \, {\left (b x + a\right )}^{\frac {11}{2}} A b^{7} + 595 \, {\left (b x + a\right )}^{\frac {9}{2}} A a b^{7} - 1386 \, {\left (b x + a\right )}^{\frac {7}{2}} A a^{2} b^{7} + 1686 \, {\left (b x + a\right )}^{\frac {5}{2}} A a^{3} b^{7} + 595 \, {\left (b x + a\right )}^{\frac {3}{2}} A a^{4} b^{7} - 105 \, \sqrt {b x + a} A a^{5} b^{7}}{a^{4} b^{6} x^{6}}}{7680 \, b} \]
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Time = 0.14 (sec) , antiderivative size = 253, normalized size of antiderivative = 1.22 \[ \int \frac {(a+b x)^{3/2} (A+B x)}{x^7} \, dx=-\frac {\left (\frac {119\,A\,b^6}{1536}-\frac {17\,B\,a\,b^5}{128}\right )\,{\left (a+b\,x\right )}^{3/2}+\left (\frac {3\,B\,a^2\,b^5}{128}-\frac {7\,A\,a\,b^6}{512}\right )\,\sqrt {a+b\,x}-\frac {33\,\left (7\,A\,b^6-12\,B\,a\,b^5\right )\,{\left (a+b\,x\right )}^{7/2}}{1280\,a^2}+\frac {17\,\left (7\,A\,b^6-12\,B\,a\,b^5\right )\,{\left (a+b\,x\right )}^{9/2}}{1536\,a^3}-\frac {\left (7\,A\,b^6-12\,B\,a\,b^5\right )\,{\left (a+b\,x\right )}^{11/2}}{512\,a^4}+\frac {\left (281\,A\,b^6-116\,B\,a\,b^5\right )\,{\left (a+b\,x\right )}^{5/2}}{1280\,a}}{{\left (a+b\,x\right )}^6-6\,a^5\,\left (a+b\,x\right )-6\,a\,{\left (a+b\,x\right )}^5+15\,a^2\,{\left (a+b\,x\right )}^4-20\,a^3\,{\left (a+b\,x\right )}^3+15\,a^4\,{\left (a+b\,x\right )}^2+a^6}-\frac {b^5\,\mathrm {atanh}\left (\frac {\sqrt {a+b\,x}}{\sqrt {a}}\right )\,\left (7\,A\,b-12\,B\,a\right )}{512\,a^{9/2}} \]
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